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The correct sequence of arrangement of t...

The correct sequence of arrangement of the following compounds in order of decreasing oxidation numbers of iodine is

A

`HIO_4, HI, I_2 , IC l_5`

B

`HIO_4 , IC l_5, HI, I_2`

C

`IC l_5, HIO_4 , I_2 , HI`

D

`HIO_5 , IC l_5 , I_2, HI`

Text Solution

Verified by Experts

The correct Answer is:
D
O.N. of I in `HIO_4 = +7`
O.N. of I in `HI` = -1
O.N. of I in `IC l_5 =+5`
O.N. of I in `I_2`=0.
Therefore decreasing order of O.N. is :
`HIO_4 gt IC l_5 gt I_2 gt HI`
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DINESH PUBLICATION-THE HALOGEN FAMILY-REVISION
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