CuCl is sparingly soluble in water but it dissolves in KCl solution due to the formation of

Options

A. `K_(2)[CuCl_(4)]`
B. `K_(2)[CuCl_(4)]`
C. `K[CuCl_(2)]`
D. None of the above.

Answer

A

Explanation

Hybrid state of Ni in `Ni(CO)_(4)` is `sp^(3)` Ni(0) has configuration `3d^(8)4s^(2)`. At the time of bonding two electrons of 4s-level go to 3d-orditals the 4s and 4p-orbitals hybridise to assume `sp^(3)` hybrid state.