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[Cu(NH(3))(4)]^(2+) is a square planar c...

`[Cu(NH_(3))_(4)]^(2+)` is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectively

A

4, `dsp^(2)`

B

1, `sp^(2)`

C

1, `dsp^(2)`

D

4s, `sp^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`[Cu(NH_(3))_(4)]^(2+)` is square planar with one unpaired electron and `dsp^(2)`-hybridization of Cu.
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