A coordination compound of cobalt has the molecular, formula containing five ammonia molecules, one nitro group and two chlorine atoms for onew cobalt atom. One mole of this compounds three ions in an aqueous solution. On reacting this solution with excess of `AgNO_(3)` solution, we get two moles of AgCI precipitate. The ionic formula for this complex would be

Options

A. `[Co(NH_(3))_(4)NO_(2)Cl](NH_(3))Cl]`
B. `[Co(NH_(3))_(5)Cl][Cl(NO_(2))]`
C. `[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`
D. `[Co(NH_(3))]_(5).[(NO_(2))_(2)Cl_(2)]`.

Answer

C

Explanation

The molecular formula of complex is `Co(NH_(3))_(5)NO_(2)Cl_(2)`. As the one mole of compound produces two moles of AgCl with `AgNO_(3)(aq)`, it has two ionisable `Ci^(-)` ions per molecule. Thus , possible ionic formula is `[Co(NH_(3))_(5)No_(2)]Cl_(2)` . It ionises to produce one `[Co(NH_(3))_(5)NO_(2)]^(2+)` and two `Cl^(-)` ions i.e. , in all three ions per molecule.