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Coordination number of Ni in [Ni(C2O4)3]...

Coordination number of `Ni` in `[Ni(C_2O_4)_3]^(4-)` is:

A

3

B

6

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
`C_(2)O_(4)^(2-)` is a bidentate group . As the complex contains three bidentate groups , the central metal ion has a co-ordination number of 6
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