Consider the following complex `[Co(NH_(3))_(5)CO_(3)]ClO_(4)`
The coordination number, oxidation number number of d-electrons and number of unpaired d-electrons on the metal are respectively

Options

A. 6, 3, 6, 0
B. 7, 2, 7, 1
C. 7, 1, 6, 4
D. 6, 2, 7, 3

Answer

A

Explanation

`[Co(NH_(3))_(5)CO_(3)]ClO_(4)`
C.N. of Co = 6 , O.S. of `Co^(2+) is +3`
It contain `Co^(3+)` as the centrl metal ion
Co(Z = 27 ) : `[Ar^(18)]4s^(2)3d^(7)`
`Co^(3+) : [Ar^(18)]3d^(6)`
No. of d-electrons in metal ion = 6
`CO_(3)^(2-)` and `NH_(3)` being strogands will forcr the six 3d-electrons to pair up in three d-orbital . This is followed up `d^(2)sp^(3)`- hybridisation to give octahedral complex. The complex have no unpaired electron.