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Hybridization shape and magnetic moment ...

Hybridization shape and magnetic moment of `K_(3)[Co(CO_(3))_(3)]` is

A

`d^(2)sp^(3)`, octahedral , `4.9` BM

B

`sp^(3)d^(2)` , octahedral , `4.9`BM

C

`dsp^(2)`, square planar octahedral , `4.9`BM

D

`sp^(3)`, tetrahedral, `4.9` BM

Text Solution

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The correct Answer is:
B

In each case the magnetic moment is `4.9` BM. It show that each of them has 4 unpaired electrons . Further, in the given complex, oxidation state of cobalt is `+3` . Hence it has `3d^(6)` configuration

`:.` hybridization is `sp^(3)d^(2)` i.e. outer orbital (high spin) octahedral.
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