The geometry of `Ni(CO_(4))` and `Ni(PPh_(3))_(2)Cl_(2)` are

Options

A. both square planar
B. tatrahedral and square planar
C. both tetrahedral
D. square planar and tetrahedral .

Answer

C

Explanation

Both `[Ni(CO)_(4)] and [Ni(PPh_(3))_(2)Cl_(2)]` are tetrahedral. Ni(Z =28) : `[Ar]^(18) 4s^(2) 3d^(8)`
`Ni(CO)_(4)` : Two 4s-electrons pairs up with 3d-electrons followed by `sp^(3)` hybridisation to give a tetrahedral complex.
`[Ni(PPh_(3))_(2)Cl_(2)]` : It has `Ni^(2+)` ion with outer configuration of `3d^(8). Ni^(2+)` undergoes `sp^(3-)`-hybridisation `(PPh_(3)) or Cl^(-)` an not force the d-electrons to pair up) and complex is tetrahedral.