A mixture `x` containing 0.02 mol of `[Co(NH_(3))_(5) SO_(4)]Br` and 0.02 mol of `[Co(NH_(3))_(5)Br]SO_(4)` was prepared in `2 L` of solution.
`1 L` of mixture `X + ` excess `AgNO_(3) rarr Y`
`1 L` of mixture `X +` excess `BaCl_(2) rarr Z`
The number of moles of `Y` and `Z` are

Options

A. `0.01, 0.01`
B. `0.02, 0.01`
C. `0.01, 0.02`
D. `0.02, 0.02`

Answer

A

Explanation

1 L of solution X contains `0.01` mol of `[Co(NH_(3))_(5)SO_(4)]Br` and gives `0.01` mol of AgBr .
`:.` Y = `0.01`
Similarly , 1L of solution X has `0.01` mol of `SO_(4)^(2-)` ions and thus , will form `0.01` mol of `BaSO_(4)`
`:.` Z = `0.01`