Nickel `(Z=28)` combines with a uninegative monodentate ligand `X^(-)` to form a paramagnetic complex `[NiX_4]^(2-)`. The number of unpaired electron(s) in the nickel and geometry of this complex ion are, respectively:

Options

A. one , square planar
B. two, square planar
C. one, tetrahedral
D. two, terahedral.

Answer

D

Explanation

As the complex `|NiX_(4)|^(2-)` is paramgnetic and the ligand `X^(-)` is uni negative monodentate , Ni is in `+2` state with the configuration

Hence hydridization is `sp^(3)` i.e. complex will be tetarhedral with two unpaired electrons.