`Ag^(+)+hArr|Ag(NH_(3))_(2)|^(+), k_(1) = 6.8 xx 10^(-3)`
`[Ag(NH_(3))]^(+) + NH_(3)hArr |Ag(NH_(3))_(2)|, k_(2) = 1.6xx10^(-3)`
Then the formation constant or `|Ag(NH_(3))_(2)|^(+)` is

Options

A. `1.08 xx 10^(-7)`
B. `1.08 xx 10^(-5)`
C. `1.08 xx 10^(-9)`
D. none of these

Answer

B

Explanation

As the reaction takes place in two stages
`k = k_(1)xx k_(2) = (6.8 xx 10^(-3)) xx (1.6xx 10^(-3))`
= `10.8 xx 10^(-6) = 1.08xx 10^(-5)`