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Which 0.01 mole of a cobalt complex is t...

Which `0.01` mole of a cobalt complex is treated with excess silver nitralte solution`4.305` g silver chloride is precipitated. The formula of the complex is

A

`[Co(NH_(3))_(3)Cl_(3)]`

B

`[Co(NH_(3))_(5)Cl]Cl_(2)`

C

`[Co(NH_(3))_(6)]Cl_(3)`

D

`[Co(NH_(3))_(4)Cl_(2)]No_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`4.305` g AgCl = `4.305/143.5` mole = `0.03` mole
As `0.01` mole of the complex gives `0.03` mole of AgCl, this shows that there are 3 ionisable Cl.
`:.` the formula is `[Co(Nh_(3))_(6)]Cl_(3)` .
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DINESH PUBLICATION-CO-ORDINATION COMPOUNDS -SELECTED STRAIGHT OBJECTIVE TYPE MCQS
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