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The complex which has the highest magnet...

The complex which has the highest magnetic moment among the following is

A

`|CoF_(6)|^(3-)`

B

`|Co(NH_(3))_(6)|^(3+)`

C

`|Ni(NH_(3))_(4)|^(2+)`

D

`|Ni(CN)_(4)|^(2-)`

Text Solution

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The correct Answer is:
To determine which complex has the highest magnetic moment, we need to analyze the number of unpaired electrons in each complex and then calculate the magnetic moment using the formula: \[ \mu = \sqrt{n(n + 2)} \] where \( n \) is the number of unpaired electrons. ### Step-by-Step Solution 1. **Identify the complexes and their oxidation states:** - Option 1: Cobalt hexafluoride \( [CoF_6]^{3-} \) - Option 2: Cobalt ammine \( [Co(NH_3)_6]^{3+} \) - Option 3: Nickel ammine \( [Ni(NH_3)_4]^{2+} \) - Option 4: Nickel tetracyanide \( [Ni(CN)_4]^{2-} \) 2. **Determine the oxidation state and electronic configuration:** - **Cobalt in \( [CoF_6]^{3-} \)**: - Oxidation state: +3 - Electronic configuration of Co: \( [Ar] 4s^2 3d^7 \) - For Co\(^{3+}\): Remove 2 from 4s and 1 from 3d → \( 3d^6 \) - Fluoride is a weak field ligand, so no pairing occurs. - Unpaired electrons: 4 - **Cobalt in \( [Co(NH_3)_6]^{3+} \)**: - Oxidation state: +3 - Electronic configuration: \( 3d^6 \) - Ammonia is a strong field ligand, causing pairing. - Unpaired electrons: 0 - **Nickel in \( [Ni(NH_3)_4]^{2+} \)**: - Oxidation state: +2 - Electronic configuration of Ni: \( [Ar] 4s^2 3d^8 \) - For Ni\(^{2+}\): Remove 2 from 4s → \( 3d^8 \) - Ammonia is a strong field ligand, causing pairing. - Unpaired electrons: 0 - **Nickel in \( [Ni(CN)_4]^{2-} \)**: - Oxidation state: +2 - Electronic configuration: \( 3d^8 \) - Cyanide is a strong field ligand, causing pairing. - Unpaired electrons: 0 3. **Calculate the magnetic moment for each complex:** - For \( [CoF_6]^{3-} \): \[ \mu = \sqrt{4(4 + 2)} = \sqrt{24} \approx 4.9 \, \text{Bohr magnetons} \] - For \( [Co(NH_3)_6]^{3+} \): \[ \mu = \sqrt{0(0 + 2)} = 0 \] - For \( [Ni(NH_3)_4]^{2+} \): \[ \mu = \sqrt{0(0 + 2)} = 0 \] - For \( [Ni(CN)_4]^{2-} \): \[ \mu = \sqrt{0(0 + 2)} = 0 \] 4. **Conclusion:** - The complex with the highest magnetic moment is \( [CoF_6]^{3-} \) with a magnetic moment of approximately 4.9 Bohr magnetons. ### Final Answer: The complex which has the highest magnetic moment among the following is \( [CoF_6]^{3-} \).

To determine which complex has the highest magnetic moment, we need to analyze the number of unpaired electrons in each complex and then calculate the magnetic moment using the formula: \[ \mu = \sqrt{n(n + 2)} \] where \( n \) is the number of unpaired electrons. ...
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DINESH PUBLICATION-CO-ORDINATION COMPOUNDS -SELECTED STRAIGHT OBJECTIVE TYPE MCQS
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  2. The ligand N(CH(2)CH(2)NH(2))(3) is

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  3. Which one of the following has largest number of isomers?

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  4. Square planar complexes of the type MABXL (where A, B, X and L are uni...

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  5. Which of the following complex ions has geometrical isomers?

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  6. Which 0.01 mole of a cobalt complex is treated with excess silver nitr...

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  7. The correct statement with respect to the complexes Ni(CO)(4) and |Ni(...

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  8. The complex which has the highest magnetic moment among the following ...

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  9. Among |Ni(CO)(4)|, |Ni(CN)(4)|^(2-), |NiCl(4)|^(2-) species, the hybri...

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  10. Geometrical shapes of the complex formed by the reaction of Ni^(2+) wi...

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  11. Among the following complexes : K(3)[Fe(CN)(6)],[Co(NH(3))(6)]Cl(3) , ...

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  12. Which of the following facls about the complex |Cr(NH(3))(6)|Cl(3) is ...

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  13. Low spin complex of d^6-cation in an octahedral field will have the fo...

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  14. [NiCl(2){P(C(2)H(5))(2)(C(6)H(5))}(2)] exhibits temperature dependent ...

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  15. Which one of the following is an outer orbital complex and exhibits pa...

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  16. As per IUPAC nomenclature, the name of the complex [Co(H(2)O)(4) (NH(3...

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  17. Which of the following complex species is not expected to exhibit opti...

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  18. An excess of AgNO(3) is added to 100mL of a 0.01M solution of dichloro...

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  19. Consider the follwing complexes ion P,Q and R P =[FeF(6)]^(3-), Q=[V...

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  20. A magnetic moment of 1.73 B.M. will be shown by one among the followin...

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