An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .

Options

A. `0.001`
B. `0.002`
C. `0.003`
D. `0.01`

Answer

B

Explanation

The complex is `|Cr(H_(2)O)_(4)Cl_(2)|Cl` . It ionizes as `underset(1"mole")|Cr(H_(2)O)_(4)Cl_(2)|Cl hArr |Cr(H_(2)O)_(4)Cl_(2)|^(+)underset(1"mole")(+Cl^(-))`
Thus 1 mole of the complex forms 1 mole of `Cl^(-)` ions and will precipitate 1 mole of AgCl 100 mL of `0.01` M complex solution contains moles of complex = `0.01/1000xx100=0.001` mole and will precipitate `0.001` mole of AgCl.