Amongst `Ni(CO)_(4),[Ni(CN)_(4)]^(2-)` and `[NiCl_(4)]^(2-)`

Options

A. `Ni(CO)_(4) and |NiCl_(4)|^(2-)` are diamagnetic and `|Ni(CN)_(4)|^(2-)` is paramagnetic
B. `Ni(CN)_(4) and |NiCl_(4)|^(2-)` are diamagnetic and `Ni(CN)_(4)` is paramagnetic
C. `Ni(CO)_(4) and |Ni(CN)_(4)|^(2-)` are diamagnetic and `|NiCl_(4)|^(2-)` paramagnetic
D. `|NiCl_(4)|^(2-) and |Ni(CN)_(4)\^(2-)` are diamagnetic and `Ni(CO)_(4)` is paramagnetic.

Explanation

To determine the magnetic properties of the coordination compounds `Ni(CO)_(4)`, `[Ni(CN)_(4)]^(2-)`, and `[NiCl_(4)]^(2-)`, we will analyze the oxidation states, electronic configurations, and the nature of the ligands involved.

### Step-by-Step Solution:

1. **Identify the oxidation state of Nickel in each complex:**
- For `Ni(CO)_(4)`: Nickel is in the 0 oxidation state.
- For `[Ni(CN)_(4)]^(2-)`: Nickel is in the +2 oxidation state.
- For `[NiCl_(4)]^(2-)`: Nickel is also in the +2 oxidation state.
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