When white eyed and miniature winged Drosophila melanogaster is crossed with its wild type it produces following percent of recombinations

Options

A. `1.3%`
B. `37.2%`
C. `62.8%`
D. `98.7%`

Answer

To solve the problem of determining the percentage of recombinations when white-eyed and miniature-winged Drosophila melanogaster is crossed with its wild type, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Parental Traits**:
- The parental traits in this cross are white eyes and miniature wings (mutant traits) and red eyes with normal wings (wild type traits).
- Mutant alleles:
- White-eyed (w)
- Miniature wings (m)
- Wild type alleles:
- Red-eyed (W)
- Normal wings (M)

2. **Cross the Parents**:
- The cross involves a female Drosophila with white eyes and miniature wings (w m) and a male Drosophila with wild type traits (W M).
- The F1 generation will consist of all offspring showing the wild type phenotype (W M) since wild type traits are dominant.

3. **Analyze the F2 Generation**:
- When the F1 individuals are crossed (W M x W M), we will observe the segregation of traits in the F2 generation.
- The F2 generation will show a combination of parental and recombinant phenotypes.

4. **Determine Recombinant and Parental Phenotypes**:
- Parental phenotypes:
- Wild type (W M)
- White-eyed and miniature wings (w m)
- Recombinant phenotypes:
- White-eyed with normal wings (w M)
- Red-eyed with miniature wings (W m)

5. **Calculate the Percentage of Recombinants**:
- In Morgan's experiments, it was noted that the percentage of recombinants was around 36.9%.
- The closest option provided in the question is 37.2%, which indicates the percentage of recombination.

6. **Conclusion**:
- The percentage of recombinants when white-eyed and miniature-winged Drosophila is crossed with its wild type is approximately 37.2%.

### Final Answer:
The percentage of recombinations is approximately **37.2%**.

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