Ethyl acetoacetate when reacts with one mole methyl magnesium iodide then product of reaction will be :

Formaldehyde when reacted with methyl magnesium bromide gives

" Ethyl acetate is treated with excess of methyl magnesium iodide in dry ether.The reaction mixture is then treated with water.The organic products obtained a "

Acetaldehyde reacts with ethyl magnesium bromide to give a product which on hydrolysis gives :

Ethyl acetate is obtained when methyl magnesium iodide reacts with

Ethyl alcohol cannot be used as solvent for methyl magnesium iodide because