Prove that : `sin^2(72^@) - sin^2 (60^@) = (sqrt5 - 1)/8`

Prove that: sin^(2)(72^(@))-sin^(2)(60^(@))=(sqrt(5)-1)/(8)

Show that sin^2 72^@ - sin^2 60^@ = (sqrt 5-1)/8

Prove that : sin^2 24^@ -sin^2 6^@= 1/8 (sqrt5-1) .

Provet that: sin^(2)72^(2)-sin^(2)60^(2)=(sqrt(5)-1)/(8)

sin ^(2) 24 ^(@) - sin ^(2) 6^(@) = (sqrt5 -1)/(8).

Prove that (i) "sin"^(2) 24^(@) - sin^(2) 6^(@) =((sqrt(5)-1))/(8) " "(ii) "sin"^(2) 72^(@) - cos^(2) 30^(@) =(sqrt(5)-1)/(8)

Given that sin18^@=(sqrt5-1)/4 prove that sin^2 24^@-sin^2 6^@=(sqrt5-1)/8

Prove that: sin^(2)24^(0)-sin^(2)6^(0)=(sqrt(5)-1)/(8)

Prove that: sin^(2)24^(0)-sin^(2)6^(0)=(sqrt(5)-1)/(8)

Prove that sin^2 48^@ - cos^2 12^@ = - (sqrt(5) +1)/8