The electronic configuration of a dipositive ion `M^(2+)` is 2, 8, 14 and its atomic mass is 56. what is the number of neutrons in its nucleus ?

Explanation

To find the number of neutrons in the nucleus of the dipositive ion \( M^{2+} \) with an electronic configuration of 2, 8, 14 and an atomic mass of 56, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electronic Configuration**:
The electronic configuration of the ion \( M^{2+} \) is given as 2, 8, 14. This means that the total number of electrons in the ion is:
\[
2 + 8 + 14 = 24 \text{ electrons}
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