Calculate the wavelength of a photon in Angstrons having an energy of 1 electron-volt.

Explanation

Energy of photon ` 1eV=1.602 xx 10^(-19)J`
`h=6.626 xx 10^(-34)Js, c=3xx10^(8)ms^(-1)`
`E=hv=(hc)/(lambda)` or `lambda= (hc)/(E)`
By substituting the values, `" " lambda=((6.626 xx 10^(-34) Js)xx (3xx10^(8)ms^(-1)))/((1.602 xx 10^(-19)J))=12.42 xx 10^(-7)m`
`=12.42 xx 10^(-7) xx 10^(10) Ã… or 12.42 xx 10^(3) Ã…`.