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A 100 watt buble emits monochromatic lig...

A 100 watt buble emits monochromatic light of wavelength 400 nm. Then the number of photons emitted per seccond by the buble is nearly -

Text Solution

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Powerof the bulb = 100 watt = `100js^(-1)`
Energy of one photon `(E)=hv=(hC)/(lambda)`
` =((6.626 xx 10^(-34)Js)xx (3xx 10^(8)ms^(-1)))/((400xx10^(-9)m))=4.969 xx 10^(-19)J`
No. of photons emitted `=("Total energy (power) of the bulb ")/("Energy of one photon")`
`=((100Js^(-1)))/((4.969xx10^(19)J))=2.012 xx 10^(20) s^(-1)`
`:. ` No. of photons emitted per second `=2.012 xx 10^(20)`
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