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A proton is accelerated to one tenth of ...

A proton is accelerated to one tenth of velocity of light. If the velocity can be measured with a precision of ` +-0.5 %`, what must be the uncertainty in its position ? `( m_(p)=1.675 xx 10^(-27)kg)`.

Text Solution

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According to uncertainty principle, ` Deltax.mDeltaupsilon=(h)/(4 pi) ""or""or Deltax=(h)/(4pim //Delta upsilon)`
Velocity of proton ` (upsilon)=(1)/(10)xx3xx10^(8)ms^(-1)=3xx10^(7) ms^(-1)`.
`Delta upsilon = 0.5 % xx of 3 xx 10^(7)=0.5 xx 10^(-2)xx3xx10^(7) " " =1.5 xx 10^(5) ms^(-1)`.
`m=1.675 xx 10^(-27) kg, h=6.626 xx 10^(-34) kg m^(2)s^(-1)`.
`Delta x = ((6.626 xx 10^(-34)kgm^(2) s^(-1)))/(4xx3.143 xx (1.675 xx 10^(-27)kg)xx (1.5 xx 10^(5)ms^(-1)))=2.1 xx 10^(13)m`.
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