If a body weighing 1.0g is travelling along x axis at 100 cm `s^(-1)` within 1 cm `s^(-1)`, what is the theoretical uncertainty in its position ?

Explanation

According to uncertainty principle,
`Delta xmDeltaupsilon =(h)/(4 pi) or Deltax=(h)/(4 pi m Delta upsilon)`
Since there is uncertainty of 1 cm `s^(-1)` in measuring velocity, the means that velocity varies between 99 xm `s^(-1)` to 101 cm ` s^(-1) or Delta upsilon = (upsilon_(2)-upsilon_(1))=(101-99)=2 cm s^(-1) or 0.02 m s^(-1)`.
`Deltax=6.626 xx 10^(-34) kg m^(2)s^(-1), m=1.0g =10^(-3)kg`
`Delta x=((6.626xx10^(-34)kgm^(2)s^(-1)))/(4xx3.143 xx (10^(-3)kg)xx (0.02ms^(-1)))=2.636 xx 10^(-30)m`