Calculate the wavelength of an electron moving with a velocity fo ` 2. 05 xx 10^7 ms^(-1)`.

Explanation

According to de Broglie's equation , `lambda=(h)/(m upsilon)`
Mass of electron (m)`=9.1xx10^(-31)`kg
Velocity of electron (v)`=2.05xx10^(7) ms^(-1)`
Planck's constant (h) `=6.626xx10^(-34)kgm^(2)s^(-1)`
`:. " " lambda=((6.626xx10^(-34)kg m^(2)s^(-1)))/((9.1xx10^(-31)kg)xx(2.05xx10^(7)ms^(-1)))=3.55xx10^(-11)m`.