If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long.

Explanation

Length of scale = 20 cm = `20xx10^(7) nm = 2xx10^(8)nm`
Diameter of carbon atom = 0.15 nm
`:. ` Number of carbon atoms which can be placed side by side in the scale ` =((2xx10^(8)nm))/((0.15 nm))`
` =1.33 xx 10^(9)`