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In Rutherford's experiment, generally th...

In Rutherford's experiment, generally the thin foil of heavy atoms, such as gold, platinum, etc. have been used to be bombarded by the `alpha`-particles. If the thin foil of light atoms such as aluminium etc. is used, what difference would be observed form the above results?

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We have studied that in the Rutherford 's experiment by using heavy metals like gold and platinum, a large number of `alpha` - particles sufferred deflection while a very few had to retrace their path . If a thin foil of lighter atoms like aluminium etc. be used in the Rutherford experiment, this means that the obstruction offered to the path of the fast moving `alpha`-particles will be comparatively quite less. As a result,the number of `alpha`- particles will be quite less and the particles which are deflected back will be negligible.
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In interperting Rutherford's experiments on the scattering of alpha particle by thin foils, one must examine what were known factors, and what the experiment settle. Which of the following are true in this context?

Rutherford's alpha particle scattering experiment on thin gold foil was responsible for the discovery of

If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been :

What do you think would be the observation if the alpha -particle scattering experiment is carried out using a foil of a metal other than gold ?

Assertion (A) : In Rutherford's experiment, alpha particles from a radium source were allowed to fall on a 10^(-4)mm thick gold foil. Most of the particles passed straight through the foil. Reason (R) : The entire positive charge and nearly whole of the mass of an atom is concentrated in the nucleus.

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Rutherford's alpha -particle scattering led to the conclusion that:

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