An ion with mass number `37` possesses one unit of negative charge. If the ion contains `11.1%` more neutrons than the electrons, find symbol of the ion.

Explanation

Let the no. of electron in the ion = x
`:. " "` the no. of protons = x-1 (as the ion has one unit negative charge)
and the no. of neutrons `=x+(x xx 11.1 )/(100) = 1.111x`
Mass no. or mass of the ion = No. of protons + No. of neutrons
(x-1 + 1.111 x)
Given mass of the ion = 37 `:. " " x-1 +1.111 x = 37 or 2.111 x = 37 + 1 38`
`x=(38)/(2.111)=18`
No. of electrons = 18 , No. of protons = 18 - 1 = 17
Atomic no. of the ion = 17 , Atom corresponding to ion = Cl
Symbol of the ion `=._(17)^(37)Cl^(-)`