Answer the following :
(a) How many electrons can be filled in all the orbitals with n + l= 5 ?
(b) Which of the two is paramagnetic, V (IV) orV (V) and why ?
(c) How many unpaired electrons are present in Pd (Z=46)?
(d) The ion of an element has configuration `[Ar] 3d^(4)` in +3 oxidation state. What will be the electronic configuration of its atom ?

Explanation

(a) (n+1)=5 has 5s, 4p and 3d orbitals with two, six and ten electrons respectively.Therefore, the total number of electrons is 18.
(b) The configuration are , V (IV) , `[Ar]^(18)3d^(1)` and `V (IV) : [Ar]^(18)`. Therefore , V (IV) is paramagnetic in nature due to the presence of unpaired electron.
(c) The electronic configuration of the element palladium `(Z=46) "is" [Kr]^(36)4d^(10)5s^(0)`. Therefore , it has no unpaired electron.
The configuration of ion is `[Ar]3d^(4)`. Therefore , the configuration of the atom is `[Ar]3d^(5)4s^(2)`.