Find the number of quanta of radiations of frequency `4.67xx10^(13)s^(-1)`, that must be absorbed in order to melt 5 g of ice. The energy required to melt 1 g of ice is 333J.

Explanation

Energy required to melt 1 g of ice = 333 J
Energy required to melt 5 g or ice =333xx5=1665 J
Energy associated with one photon `=hv=(6.62xx10^(-34)J s)xx(4.67xx10^(13)s^(-1))`
`=30.91xx10^(-21)J`
Number of photons required to melt 5 g or ice `=((1665 J))/((30.91xx10^(-21)J))=5.38xx10^(22)`.