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One quantum is absorbed per molecule of gaseous iodine for converting into iodine atoms. If light absorbed has wavelength of `5000A^(@)`, The energy required in `kJ mol^(-1)` is

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`E=N_(0)hv=(N_(0)hc)/(lambda)`
`=((6.022xx10^(23)"mol"^(-1))xx(6.626xx10^(10^(-34)Js))xx(3xx10^(8)ms^(-1)))/((5000xx10^(-10)m))`
`=239.3xx10^(3)J "mol"^(-1)=239.3kJ "mol"^(-1)`
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