What is the ratio between the energies of two radiations one with a wavelength of 6000Ã… and other with 2000Ã…?

Answer

`E_(2)=3E_(1)`

Explanation

`lambda_(1)6000 Ã… , lambda_(2)=2000Ã…`. ltbegt `E_(1)=h (C)/(lambda_(1)) "and" E_(2)=(hc)/(lambda_(2))`
`(E_(1))/(E_(2))=(lambda_(2))/(lambda_(1))=(2000)/(6000)=(1)/(3) " " E_(2)=3E_(1)`