Calculate the wavelength from the Balmer formula when `n_(2)=3.`

Answer

`lambda=656 nm`

Explanation

According to Balmer formula : `bar(v)=109678[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]cm^(-1)`
`bar(v)=109678[(1)/(2^(2))-(1)/(x^(2))]cm^(-1)=(109678xx5)/(36) cm^(-1). " " `(`:.n_(1)=2, n_(2)=3`)
Wave length `(lambda)=(1)/(bar(v))=(36)/(109678xx5)cm=6.56xx10^(-5)cm=6.56xx10^(-5)xx10^(7) nm = 656 nm`