The kinetic energy of a sub-atomic particle is `5.65xx10^(-25)J`. Calculate the frequency of the particle wave.

Answer

`1.705xx10^(9) s^(-1)`

Explanation

Kinetic energy (K.E.) of the sub-atomic particle =`1//2mv^(2)`
According to de Broglie relationship, `(lambda)=(h)/(m upsilon)`
Frequency of the matter wave, (v) `("Velocity of matter wave")/("Wavelength of matter wave")=(upsilon)/(lambda)`
Substituting the value of `lambda` in equation (ii)
Frequency `(v)=(upsilon)/(h//m upsilon)=(m upsilon^(2))/(h)=(2xx(1)/(2) m upsilon^(2))/(h) =(2K.E.)/(h)`
Substituting the values of kinetic energy and h , `v=((2xx5.65xx10^(-25)J))/((6.626xx10^(-34)Js))=1.705xx10^(9)s^(-1)`.