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Calculate the momentum of a particle whi...

Calculate the momentum of a particle which has de Broglie wavelength of 0.1 nm.

Text Solution

Verified by Experts

The correct Answer is:
`6.626xx10^(-24)"kg "m s^(-1)`
According to de Broglie equation, `lambda=(h)/(m v)=(h)/(p) or p=(h)/(lambda)`
`p=((6.626xx10^(-34) "kg" m^(2)s^(-1)))/((0.1xx10^(-9)m))=6.626xx10^(-24) "kg"m s^(-1)`.
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Knowledge Check

  • The momentum of a particle having de-Broglie wavelength of 6 Å

    A
    `1.1xx10^(34)kg-m//s`
    B
    `39.6xx10^(-34) kg-m//s`
    C
    `1.1xx10^(-24)kg-m//s`
    D
    `39.6xx10^(-24)kg-m//s`

  • The momentum of a particle which has a de Broglie wavelength of 2.5 xx 10^-10 m is.

    A
    `2.64 xx 10^-24 kg m sec^-1`
    B
    `3.62 xx 10^-24 kg m sec^-1`
    C
    `4.64 xx 10^-24 kg m sec^-1`
    D
    `3.62 xx 10^-26 kg m sec^-1`

  • The momentum of a paricle which has a d-Broglie wavelength of 0.1 nm is ( h= 6.6 xx10^(-34) J s)

    A
    `3.2 xx10^(-24) kg ms^(-1)`
    B
    ` 4.3 xx10^(-22) kgms^(-1)`
    C
    ` 5.3 xx 10^(-22) kgms^(-1)`
    D
    ` 6.62 xx 10^(-24) kg ms^(-1)`

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    Calculate the momentum of a particle which has a de Brglie wavelength of 1 Å or 0.1 nm. (h = 6.6 xx 10^(-34) kg m^(2) s^(-1))

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    Calculate the momentum of the particle which has de Broglie wavelength 1"Ã…"(10^(-10)m) and h=6.6xx10^(-34)J-sec .

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    The momentum of a particle associated with de-Broglie's wavelength of 6 Å is

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