An electron is moving with a kinetic energy of `2.275xx10^(-25)J` . Calculate its de Broglie wavelength.

Answer

`1.04xx10^(-6)m s^(-1)`

Explanation

Kinetic energy `=1//2mv^(2)=2.275xx10^(-25)J=2.275xx10^(-25) "kg "m^(2) s^(-2)`
`v^(2)=(2xx K.E.)/(m)=(2xx(2.275xx10^(-25) "kg"m^(2)s^(-2)))/((9.1xx10^(-31)"kg"))=0.5xx10^(6)m^(2)s^(-2)`
`lambda=(h)/(mv)=((6.626xx10^(-34)"kg"m^(2)s^(-1)))/((9.1xx10^(-31)"kg")(0.7xx10^(3)m))=1.04xx10^(-6)ms^(-1)`.