Calculate the de Broglie wavelength of an electron moving at 1.5% of the speed of light.

Answer

`1.62XX10^(-10)m`

Explanation

According to de Broglie equation , `lambda=(h)/(m v)`
`m=9.1xx10^(-31) "kg", h=6.626xx10^(-34) "kg" m^(2)s^(-1)`,
`v=(1.5xx3xx10^(8))/(100)=4.5xx10^(6) m s^(-1)`
`lambda=((6.626xx10^(-34) "kg"m^(2)s^(-1)))/((9.1xx10^(-31) "kg")xx(4.5xx10^(6)ms^(-1)))=1.62xx10^(-10)m`.