what will be uncertainty in the velocity of an electron if it is located within `5xx10^(-5)Ã…` ?

Answer

`1.16xx10^(10)m s^(-1)`

Explanation

According to uncertainty principle,
`Delta*m Delta v=(h)/(4 pi) or Deltav=(h)/(4 pixxmxxDelta x)`
`h=6.626xx10^(-34) "kg"m^(2)s^(-1), Deltax=5xx10^(-5)Ã…=5xx10^(-10)=5xx10^(-15)m`,
`:. " " Deltav=((6.626xx10^(-34) "kg" m^(2)s^(-1)))/(4xx3.143xxx(9.1xx10^(-31) "kg" )xx(5xx10^(-15) m))=1.16xx10^(10)ms^(-1)`.