Calculate the uncertainty in the position of an electron if the uncertainty in its velocity is `5.77xx10^(5) m s^(-1)`.

Answer

`10^(-10)m`

Explanation

According to uncertainty principle, `Deltax.m Deltav=(h)/(4pi) or Deltax=(h)/(4 pim Delta v)`
`Deltav=5.77xx10^(5)m s^(-1), m=9.1xx10^(-31) "kg" h=6.62xx10^(-34)"kg"m^(2)s^(-1) , pi=3.143`
`Deltax=((6.626xx10^(-34)"kg"m^(2)s^(-1)))/(4xx3.143xx(9.1xx10^(-31)"kg")xx(5.77xx10^(5) ms^(-1)))=10^(-10)m`.