Out of the folowing paris of electorns, identify the pairs of electrons present in degenrate orbitals.

Options

A. `(i) n=3, l=2, m_(l)=-2, m_(s)=-(1)/(2)`
`(ii) n=3, l=2, m_(l)=-1, m_(s)=-(1)/(2)`
B. `(i)n=3, l=1, m_(l)=1, m_(s)=+(1)/(2)`
`(ii)n=3, l=2, m_(l)=1, m_(s)=+(1)/(2)`
C. `(i) n=4, l=1, m_(l)=1, m_(s)=+(1)/(2)`
(ii)`n=3, l=2, m_(l)=1, m_(s)=+(1)/(2)`
D. `(i)n=3, l=2, m_(l)=+2, m_(s)=-(1)/(2)`
`(ii) n=3, l=2, m_(l)=+2, m_(s)=+(1)/(2)`

Answer

A, D

Explanation

The pair of electrons in both the options have same values for all the four quantum numbers. Therefore, these are present in degenerate orbitals i.e. orbitals of same energy state.