The electronic configuration of copper is `[Ar] 4s^(1) 3d^(10)` and not `[Ar] 4s^(2) 3d^(9)`. Justify.

The electronic configuration of valence shell of Cu is 3d^(10)4s^(1) and not 3d^(9)4s^(2) . How is this configuration explained?

Electronic configuration of M^(3+) is [Ar]3d^(10)4s^(2) , it belongs to

Electronic configuration of ._23 V^(3+) ion is [Ar]^18 3 d^2 and not [Ar] 18 3d^0 4 s^2 . V^(3+) ion is diamagnetic in nature.

The element with electronic configuration 3d^(5)4s^(1) is

The electron configuration of the element 'M' is [Ar] 3d^(10) 4s^(2) 4p^(3) . Then 'M' belong to

Element with electronic configuration as [Ar]^(18)3d^(5)4s^(2) is placed in :