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Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` is

A

5, 1, 1, +1/2

B

6, 0, 0, +1//2

C

5, 0, 0 , +1/2

D

5, 1, 0, +1/2

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The correct Answer is:
C

For Rubedium (Rb), Z=37. Its electrons configuraion is `[Kr]^(36) 5s^(1)`. The four sets of quantum numbers for 5s electron are `5, 0, 0, +1//2 or -1//2`,
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