Uncertainty in position of mass ` 25 g` in space is ` 10^(-5) m`. The uncertainty in it's velocity (in `ms^(-1)` is :

Options

A. `2.1xx10^(-34)`
B. `0.5xx10^(-34)`
C. `2.1xx10^(-28)`
D. `0.5xx10^(-23)`

Answer

C

Explanation

`Deltav=(h)/(4pi m Delta x)`
`=((6.60xx10^(-34)Kg m^(2) s^(-1)))/(4xx3.143xx(15xx10^(-3)Kg)xx(10^(-5)m))=2.1xx10^(-28) ms^(-1)`