A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu. If c and m are charge and mass of an electron repectively, then the value of `h//lambda` (where `lambda` is wavelength associated with electron wave) is given by :

Options

A. meV
B. 2meV
C. `sqrt(meV)`
D. `sqrt(2 me V)`

Answer

D

Explanation

According to de Broglie Equation,
`lambda=(h)/(m upsilon)=(h)/((mxx2 KE)^(1//2)`
`lambda=(h)/((mxx2eV)^(1//2)) " " (. :' KE=eV)`
`(h)/(lambda)=(2pir)/(nh)=(mxx22eV)^(1//2)`