Correct set of four quantum numbers for the valence (outermost) electron of rubidium `(Z = 37)` is

Options

A. `5, 0, 0, + (1)/(2)`
B. `5, 1, 0, +(1)/(2)`
C. `5, 1, 1, +(1)/(2)`
D. `6, 0, 0, +(1)/(2)`

Answer

A

Explanation

The electronic configuration rubidium (Z=37) is `[Kr]^(36)5s^(1)` For 5s electron ,
`n=5, l=0, m=0, s=+(1)/(2)`