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The equilibrium constant for the reactio...

The equilibrium constant for the reactions have been measured at 823 K.
`CoO(s) + H_(2)(g) hArr Co(s) + H_(2)O(g) , K = 67`
`CoO(s) + CO(g) hArr Co(s) + CO_(2) (g) , K = 490.`
From the data, calculate the equilibrium constant for the reaction.
`CO_(2)(g) +H_(2) (g) hArr CO(g) + H_(2)O (g)`

Text Solution

Verified by Experts

In order to find the value of K for the reaction indicated subtract second eqn. from first eqn.
`CoO(s) +H_(2)(g) hArr Co(s) +H_(2)O(g) p, K =67`
`" subtract " : (CoO(s) + CO(g) hArr Co(s) + CO_(2)(g), K =490)/(CO_(2)(g)+H_(2)(g)hArrCO(g)+H_(2)O(g) , K =67//490 = 0.137)`
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