At 300 K, the degree of dissociation of 0.066 M solution of an acid HA is 0.0145. What would be its degree of dissociation of 0.02 M solution of the acid at the same temperature?

Explanation

According to Ostwald dilution law`alpha = sqrt((K_(a))/(C))`
According to available data:
`alpha` for 0.066 M solution = 0.0145 and `alpha`' for 0.02 M solution is to be calculate. Therefore ,
`0.0145 sqrt((K_(a))/(0.066))`
`alpha'=sqrt((K_(a))/(0.02M))`
Dividing Eqm. (ii) by Eqn. (i),
`(alpha)/(0.0145) = sqrt((0.066)/(0.02)) = 1.8166 or alpha' = 0.0145 xx 1.8166 = 0.0263.`