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At 298 K, the pH of a lemon juice is 2.3...

At 298 K, the pH of a lemon juice is 2.32. Calculate its `[H_(3)O^(+)]" and "[OH^(-)].`

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To solve the problem, we will follow these steps: ### Step 1: Calculate the concentration of \( [H_3O^+] \) The pH of a solution is related to the concentration of hydronium ions \( [H_3O^+] \) by the formula: \[ \text{pH} = -\log [H_3O^+] ...
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The pH of lemon juice is

The p^(H) of lemon juice is

H_(3)O^(+)"with"OH^(-)

How will you find pH of lemon juice ?

H_(3)O^(+) + OH^(-) rarr 2H_(2)O is