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An acid solution of pH =6 is diluted 100...

An acid solution of `pH =6` is diluted `100` times. The `pH` of solution becomes

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pH of solution =6 , `[H_(3)O^(+)] =10^(-6)`
After diluting the solution to 100 times.
`[H_(3)O^(+)] =10^(-6)//100 =10^(-8) M`
`[H_(3)O^(+)]` by the dissociation of water `=10^(-7) M`
Total `[H_(3)O^(+)] =10^(-8) M+ 10^(-7) (10^(-1) +1) = 1.1 xx 10^(-7) M`
pH =- log `(1.1xx10^(-7)) =(7 -log 1.1) =(7-0.0414) = 6.9586`
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