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Calculate the percentage hydrolysis of d...

Calculate the percentage hydrolysis of decinormal solution of ammonium acetate given that
`k_(a) = 1.75 xx 10^(-5), K_(b) =1.80 xx 10^(-5) and K_(w) = 1.0 xx 10^(-14)`

Text Solution

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(i). Calculation of hydrolysis constant `(K_(h)).`
Since ammonium acetate is salt of weak acid and weak base,
`K_(h) =(K_(w))/(K_(a).K_(b)) = (1.0xx10^(-14))/(1.75xx10^(-5)xx1.80xx10^(-5))=3.175 xx10^(-5)`
(II). Calculatation of degree of hydrolysis (h).
`h=sqrt(K_(h))= (3.175 xx 10^(-5))^(1//2) =(31.75 xx 10^(-6))^(1//2) =5.63 xx 10^(-3).`
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