At `450 K, K_(p)=2.0xx10^(10)//` bar for the given reaction at equilibrium.
`2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`
What is `K_(c )` at this temperature?

Explanation

`K_(p) =K_(c) (RT)^(Deltang) or K_(c) =(K_(p))/((RT)^(Deltang))=K_(p)(RT)^(-Deltang)`
`K_(p) = 2.0 xx 10^(10) " bar"^(-1) , R =0.083 L " bar " K^(-1) mol^(-1), T 450 K, Delta^(ng) =2-3 =-1`
`K_(c) =(2.0 xx 10^(10) "bar"^(-1))xx [(0.083 L " bar " K^(-1) mol^(-1))xx (450 K)]^(-(1))`
`=7.47 xx 10^(11) mol^(-1) L=7.47 xx 10^(11)M^(-1)`